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📰 \frac{n}{n} \cdot \binom{n - k}{k} + (-1)^k \cdot \frac{n}{n - k} \cdot \binom{n - k - 1}{k - 1} 📰 But for small $n=8$, $k=3$, we use a constructive method. 📰 Fix one station as selected. By rotational symmetry, fix station 1. Then the two neighbors (8 and 2) cannot be selected. We choose 2 more from stations 3, 4, 5, 6, 7, with no two adjacent (since 4 and 5 are adjacent, etc.), and no adjacency to 1 or each other.