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Home » dm + dn = 100 \implies d(m + n) = 100 - Anadea

dm + dn = 100 \implies d(m + n) = 100 - Anadea

📅 May 14, 2026 👤 scraface

May 14, 2026

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Since $ x + y + z = 1 $, we substitute into the inequality:
S \geq 1.
To check if this bound is achievable, consider the equality condition...
Let this common value be $ k $. Then,
\frac{x^2}{y} = \frac{y^2}{z} \Rightarrow x^2 z = y^3, \quad \frac{y^2...
From these, we deduce a symmetry: suppose $ x = y = z $. Then $ x + y...
S = 3 \cdot \frac{(1/3)^2}{1/3} = 3 \cdot \frac{1/9}{1/3} = 3 \cdot \f...
Hence, the minimum value is achieved when $ x = y = z = \frac{1}{3} $.
Question: Define $ f(u) = u - \frac{u^4}{4} $. If $ n $ is a positive...
b_1 = 1, \quad b_{n+1} = f(b_n).

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