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📅 May 16, 2026 👤 scraface

May 16, 2026

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Substituting this into the original equation gives:
2\sin(\theta)\cos(\theta) = \cos(\theta).
Assuming \(\cos(\theta) \neq 0\), we can divide both sides by \(\cos(\...
2\sin(\theta) = 1.
\sin(\theta) = \frac{1}{2}.
The solutions for \(\theta\) in the interval \([0^\circ, 360^\circ]\)...
\theta = 30^\circ \quad \text{and} \quad \theta = 150^\circ.
Next, consider the case where \(\cos(\theta) = 0\). This occurs at:
\theta = 90^\circ \quad \text{and} \quad \theta = 270^\circ.
Checking these values in the original equation, we find \(\sin(180^\ci...

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