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rate of change for relation - Anadea

📅 May 15, 2026 👤 scraface

May 15, 2026

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📌 So correct claim is proven. Best choice:

📌 A) True, by definition — correct.

📌 Because in any triangle, the area is $ A = r \cdot s $, where $ s $ is semiperimeter and $ r $ is inradius. This holds for right triangles as well.

📌 Pregunta: In a right triangle with inradius $ r $ and semiperimeter $ s $, what is the relationship between the triangle’s area and $ r \cdot s $?

📌 A) Only when acute

📌 B) $ A = r^2 s $

📌 C) $ A = 2r s $

📌 D) $ A = r + s $

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