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season 11 of the x files - Anadea

📅 May 17, 2026 👤 scraface

May 17, 2026

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Also: $a_n = 2 \cdot 2^n + 3 = 2^{n+1} + 3$? Warte — Prüfe:
$a_0 = 2^1 + 3 = 5$, korrekt
$a_1 = 2^2 + 3 = 7$, aber aus Rekurs: $2 \cdot 5 - 3 = 7$, korrekt
Wait — Fehler im Vorgang:
$a_n = A \cdot 2^n + 3$
$a_0 = A + 3 = 5 \Rightarrow A = 2$
Dann $a_n = 2 \cdot 2^n + 3 = 2^{n+1} + 3$
Prüfe $a_1 = 2^{2} + 3 = 4 + 3 = 7$, und $2a_0 - 3 = 10 - 3 = 7$, korr...
Bessere Form: $a_n = 2^{n+1} + 3$ — aber $2^{n+1} + 3$ für $n=0$: $2 +...
Aber $a_n = 2 \cdot 2^n + 3 = 2^{n+1} + 3$

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