You Wont Believe What Happened on An Elmwood Trail — You’ll Never See Your Neighbor the Same Way Again!
A quiet stretch of an Elmwood Trail in small-town

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Since $\|\mathbf{x}\| = \|\mathbf{y}\| = 1$, this becomes:
+ 1 + 2\mathbf{x} \cdot \mathbf{y} = 1 \Rightarrow 2 + 2\mathbf{x} \cdot \mathbf{y} = 1 \Rightarrow \mathbf{x} \cdot \mathbf{y} = -\frac{1}{2}
This is the only possible value under the constraint, so the maximum is:

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